Considering a small portion of dr in the rod at a distance r from the axis of the rod.
So,mass of this portion will be dm=mldr (as uniform rod is mentioned)
Now,tension on that part will be the Centrifugal force acting on it, i.e dT=−dmω2r (because,tension is directed away from the centre whereas,r is being counted towards the centre,if you solve it considering Centripetal force,then the force will be positive but limit will be counted from r to l)
Or, dT=−mldrω2r
So, ∫T0dT=−mlω2∫xlrdr (as,at r=l,T=0)
So, T=−mω22l(x2−l2)=mω22l(l2−x2)
Three identical balls are placed on a frictionless
horizontal surface touching each other. They stick to
each other because of adhesive. Another ball of same
radius and mass m is placed over the void created by
the three balls. Find the forces applied by the balls
kept on the floor to each other if the system remains
in equilibrium.
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A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.
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Last Activity: 10 Months ago
Last Activity: 3 Years ago
Last Activity: 3 Years ago
