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`        A uniform rod of length l, hinged at the lower end is free to rotate in a vertical plane.  If the rod is held vertically in the beginning and then released, the angular acceleration of the rod when it makes an angle of 45°with the horizontal is ?`
one year ago

Arun
23487 Points
```							 When it makes 45 degree with the horizontal then at this position torque acting on rod is =mgl/2 cos45                                                                                                                             =mgl/2√2We know thatTorque=moment of inertia * angular accelerationmgl/2√2  =ml2/3  * angular acceleration         where m is the mass of rodangular acceleration =3g/2√2 l
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions