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Grade 12th passMechanics

A uniform rod of length 2m and mass 500g is pivoted at one end and is displaced through 60° from the vertical .What is its kinetic energy while passing through the mean position

Profile image of SASWATHAN R
6 Years agoGrade 12th pass
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3 Answers

Profile image of Arun
6 Years ago
Dear student
 
 
At mean postion the total energy would be =>
mgl/2  + 0.5Iw^2 as we are unaware of w the value that is the total energy would be equals to => mglsin60/2
Hence the Total ENERGY would be => root(3)*0.5*10*2/4  => 5root(3) J
 
Hope it helps
Profile image of Vikas TU
6 Years ago
 
At mean postion the total energy would be =>
mgl/2  + 0.5Iw^2 as we are unaware of w the value that is the total energy would be equals to => mglsin60/2
Hence the Total ENERGY would be => root(3)*0.5*10*2/4  => 5root(3) J