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A uniform rod of length 2m and mass 500g is pivoted at one end and is displaced through 60° from the vertical .What is its kinetic energy while passing through the mean position

A uniform rod of length 2m and mass 500g is pivoted at one end and is displaced through 60° from the vertical .What is its kinetic energy while passing through the mean position

Grade:12th pass

3 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Arun
25750 Points
4 years ago
Dear student
 
 
At mean postion the total energy would be =>
mgl/2  + 0.5Iw^2 as we are unaware of w the value that is the total energy would be equals to => mglsin60/2
Hence the Total ENERGY would be => root(3)*0.5*10*2/4  => 5root(3) J
 
Hope it helps
Vikas TU
14149 Points
4 years ago
 
At mean postion the total energy would be =>
mgl/2  + 0.5Iw^2 as we are unaware of w the value that is the total energy would be equals to => mglsin60/2
Hence the Total ENERGY would be => root(3)*0.5*10*2/4  => 5root(3) J

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