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Grade: 12th pass
        
A uniform rod of length 2m and mass 500g is pivoted at one end and is displaced through 60° from the vertical .What is its kinetic energy while passing through the mean position
2 months ago

Answers : (3)

Saurabh Koranglekar
askIITians Faculty
8369 Points
2 months ago
Arun
24726 Points
							
Dear student
 
 
At mean postion the total energy would be =>
mgl/2  + 0.5Iw^2 as we are unaware of w the value that is the total energy would be equals to => mglsin60/2
Hence the Total ENERGY would be => root(3)*0.5*10*2/4  => 5root(3) J
 
Hope it helps
2 months ago
Vikas TU
11682 Points
							
 
At mean postion the total energy would be =>
mgl/2  + 0.5Iw^2 as we are unaware of w the value that is the total energy would be equals to => mglsin60/2
Hence the Total ENERGY would be => root(3)*0.5*10*2/4  => 5root(3) J
2 months ago
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