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A uniform rod AB which is free to swing in the vertical plane about a horizontal axis through A, is hanging freely. A particle of equal mass strikes the rod with a velocity v and gets stuck to it. Find the angular velocity of the combination immediately after the collision.

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3 years ago

Spandan Mallick
12 Points
```							First we have to find the net moment of inertia of the setup.I = (mL^2/12)+(mL^2/2) = (7mL^2/12)Now,mvr = Iw => m. v. (L/2) = (7mL^2/12) . w=> w = 6v/7L. Hope it helps. Spandan Mallick, JEE Aspirant.
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one year ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions