Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A uniform rod AB which is free to swing in the vertical plane about a horizontal axis through A, is hanging freely. A particle of equal mass strikes the rod with a velocity v and gets stuck to it. Find the angular velocity of the combination immediately after the collision.

A uniform rod AB which is free to swing in the vertical plane about a horizontal axis through A, is hanging freely. A particle of equal mass strikes the rod with a velocity v and gets stuck to it. Find the angular velocity of the combination immediately after the collision.

Question Image
Grade:12th pass

1 Answers

Spandan Mallick
12 Points
2 years ago
First we have to find the net moment of inertia of the setup.
I = (mL^2/12)+(mL^2/2) = (7mL^2/12)
Now,
mvr = Iw 
=> m. v. (L/2) = (7mL^2/12) . w
=> w = 6v/7L.
 
Hope it helps. 
Spandan Mallick, JEE Aspirant.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free