Thiccsardar
Last Activity: 2 Years ago
NOTE- Instantaneous axis of rotation(the bottommost point) is stationary.
Moment of Inertia in frame of centre of mass= I of ring + I of particle= mR^2+ 2mr^2=3mR^2
By parallel axis theorem, Moment of inertia in frame of IAR = 3mR^2+ mR^2=4mR^2
Also, the ring performs rolling motion, So V0= RW
K.E = 1/2IW^2 = 1/2(4mR^2)(v0/R)^2 = 2mV0^2 ----ans.