A uniform ring of mass m and radius r has a particle of mass 2m rigidly attached to it on the inside surface. The system rolls on a horizontal surface without slipping. In the position shown at a certain instant, it's centre c has a velocity v.Find the kinetic energy of the system
Sonal , 5 Years ago
Grade 12
2 Answers
Arun
Last Activity: 5 Years ago
Dear Sonal
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Thiccsardar
Last Activity: 1 Year ago
NOTE- Instantaneous axis of rotation(the bottommost point) is stationary.
Moment of Inertia in frame of centre of mass= I of ring + I of particle= mR^2+ 2mr^2=3mR^2
By parallel axis theorem, Moment of inertia in frame of IAR = 3mR^2+ mR^2=4mR^2