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a uniform ring of mass 20kg and radius 0.30m is making 2100 rpm about its geometrical axis.then, the rotational Kinetic energy of the ring about the axis is ?

a uniform ring of mass 20kg and radius 0.30m is making 2100 rpm about its geometrical axis.then, the rotational Kinetic energy of the ring about the axis is ?

Grade:11

1 Answers

Vikas TU
14149 Points
7 years ago
Rotational Kinetic energy = 0.5*I*w^2 => 0.5*(mr^2)*(2100*2pi/60) 
=> 0.5*(20*0.09)*(70pi)
=> 63pi Joule.

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