×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A uniform disc of radius R is taken and out of it a disc of diameter R/2 is cut off from end. The center of mass of remaining part will be?


4 years ago

Manas Shukla
102 Points
							Let M be the mass of the full disc , M’ be the mass of the partial disc and m be the mass of the smaller removed disc. If p is the density of the disc materialsThen$M = p\Pi R^{2}$$m =\frac{1}{16} p\Pi R^{2}$$M' =\frac{15}{16} p\Pi R^{2}$Now Lets assume the centre of whole disc is at origin and thus removed disc centre is at (0,3R/4)As we see it will be symmetrical along x axis thus centre of mass along y coordinate wont change.For x coordinate we have$M\times 0 =\frac{1}{16} p\Pi R^{2} \times \frac{3R}{4} + \frac{15}{16} p\Pi R^{2} \times x$$x = \frac{-R}{20}$Thus new coordinate for CoM = (0,-R/20)

4 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions