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A uniform chain of mass m and length l overhangs a table with its two third part on the table.find the work to be done by a person to put the hanging part back on the table.

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4 years ago

Vikas TU
14146 Points
```							2/3rd part is on the table and 1/3rd is hanging.Therefore the mass corresponding the hanging length is:m mass  for  l lengththan for l/3 length mass would be:m/3. Hence potential energy would be = (m/3)g(l/3) = > mgl/9 JHence the Work done = mgl/9.
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions