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`        a uniform chain of mass M and length L has a part L/3 hanging over the edge of table. if the friction between the table and the chain is neglected the kinetic energy as i completely falls of the table is `
one year ago

Arun
23491 Points
```							 unit length of rope is M/Lgiven L/3 part of rope is hangingwe have to solve using integration methods, lets say 'x' part of rope is consided with an element 'dx' which is pulled up with limits from 0 to L/3Potential energy = mghhere dE= integral of ( Mx/L*g*dx)        E = integral of ( M/L*g*x.dx) limits from 0 to L/3    P.E = MgL/18
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions