0

Guest

Courses New

A uniform chain of length lvand mass m lies on a smooth table .a very small lart of it this chain hangs from table .it begins to fall freely under the weight of hanging chainvfind the velocity of chain when the length of hanging part becomes y

A uniform chain of length lvand mass m lies on a smooth table .a very small lart of it this chain hangs from table .it begins to fall freely under the weight of hanging chainvfind the velocity of chain when the length of hanging part becomes y

Grade:12

1 Answers

Manas Shukla
102 Points
7 years ago
Length of the chain = L
Given the chain is of uniform density and shape.
Let mass of chain = M
Hanging part of the chain = y
depth of centre of mass of the chain of hanging part = y/2
Since the chain is rigid it will move with the same speed.
Mass of the hanging part of the chain = My/L
Lets balance Energy when hanging part becomes y.
\frac{1}{2} \times M\times v^{2} = \frac{My}{L}\times g\times \frac{y}{2}
v = y\sqrt{\frac{g}{L}}
 
 
 

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More