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        A uniform chain has a mass ‘m’ and length ‘L’. it is placed on a frictionless table with length ‘l’ hanging over the edge. The chain begins to slide down. Give the speed ‘v’  with which the chain slides away from edge.
2 years ago

Arun
23340 Points
							Dear student choosing zero potential energy at the horizontal level to be zero .Initial potential of the string is Ui=−mghcentre of mass of the string=−MLlo glo2=−Mgl022LPotential energy when the string is about to leave =−MgL2Kinetic energy with which it leaes the table  K=12Mv212Mv2−MgL2=−Mglo22Lv2−gL=−glo2Lv=g(L−l2oL)−−−−−−−−−√v=gL(L2−l20

2 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions