badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A train stops at two station P & Q which are 2 km apart .It accelerates uniformly from P at 1m/s*2 for 15sec & maintains a constant speed for a time before decelerating uniformly to rest at Q the decelration is 0.5ms*2, find time for which train is travelling at constant speed

3 years ago

Answers : (1)

Kruthic
17 Points
							
When the train starts at P
Displacement in 15 seconds=ut+0.5at=0.5*1*15*15=225/2 metres.
Velocity attained=u+at=1*15=15m/s.
Let the train travel with 15m/s for t seconds.
Displacement covered by the train while travelling with constant velocity=vt=15t
While the train decelarates, v2-u2=2as
s=(v2-u2)/2a=-15*15/2(-0.5)=225metres
Total displacement=225/2+15t+225
2000=225/2+225+15t
15t=1662.5
Therefore , t=1662.5/15=110.83seconds.
 
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details