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A train stopping at two stations d distance apart takes time t on the journey from one station to other. Assuming that its motion is first of uniform acceleration α and then immediately of uniform retardation β, show that 1/α+1/β=t*t/2d

Nirupam Nishant , 9 Years ago
Grade 11
anser 1 Answers
Vikas TU
       In the question, it is not given   that the movement of the train is of uniform velocity so we can assume that half is accelerated and half is retarded that is α = β
D = distance v0  = maximum velocity
 Distance travelled = Area under v-t graph
               d = ½ v0t
             v0= 2d/t
              
 As we know that
             v02/ 2α +  v02/2 β =  d
         4d^2/2xt*t*α + 4d^2/2**t*t* β = d
           2d/t*t* α + 2d/ t*t* β  = 1
           1/ α + 1/ β = t*t /2d
Last Activity: 8 Years ago
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