Mechanics> a train starting from rest is accelerated...

a train starting from rest is accelerated its instantaneous acceleration is given by 10/v+1m/s^2 where v is the velocity in m/s find the distance in which the train attains a velocity of 54km/hr

sachidanand , 7 Years ago

Grade 11

2 Answers

Arun

Dear student

a = 10/v+1 = dv/dt

10 * dt = (v+1) dv

On integrating

10 t = v² /2 + v + c

At t = 0 , v = 0 hence c= 0

Now

10 t = 15²/2 + 15

t = 112.5 +15 /10 = 12.75 sec

Now you can find the distance

Last Activity: 7 Years ago

Ramit Inma Ashol

How to find distance pls tell fast pls pls.

Last Activity: 7 Years ago

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Mechanics> a train starting from rest is accelerated...

a train starting from rest is accelerated its instantaneous acceleration is given by 10/v+1m/s^2 where v is the velocity in m/s find the distance in which the train attains a velocity of 54km/hr

sachidanand , 7 Years ago

Arun

Ramit Inma Ashol

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