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Grade: 12th pass

                        

A thing ''A" directly collided with an another staitonary thing "B" and for this Collison "A" stopped. If in this Collison the original Kinetic energy made half then what is the value of coefficient of restitution?

2 years ago

Answers : (1)

Eshan
askIITians Faculty
2095 Points
							Dear student,

From conservation of linear momentum,

m_Av_0=m_Bv\implies v=\dfrac{m_A}{m_B}v_0

It is given that\dfrac{1}{2}m_Bv^2=\dfrac{1}{2}\implies \dfrac{1}{2}m_Bv^2=\dfrac{1}{2}\times \dfrac{1}{2}m_Av_0^2
\implies m_Bv^2=\dfrac{1}{2}m_Av_0^2

Solving the two relations gives,
\implies \dfrac{v}{v_0}=2\dfrac{v^2}{v_0^2} \implies v=\dfrac{v_0}{2}
Hence ceffcient of restitution=\dfrac{v_{sep}}{v_{app}}=\dfrac{v_0/2}{v_0}=0.5
2 years ago
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