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A thin uniform copper rod of length l and mass m rotates uniformly with an angular velocity 'w' in a horizontal plane about a vertical axis passing through one of its ends. Determine the tension in the rod as a function of the distance r from the rotation axis. Find the elongation of the rod. please give a clear solution and if possible in two different ways.

Radhika Batra , 11 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

To analyze the tension in a rotating copper rod and determine its elongation, we can approach the problem using two different methods: one based on the principles of circular motion and the other using Hooke's Law for elasticity. Let's break this down step by step.

Understanding the Forces in Play

When the rod rotates about a vertical axis, each segment of the rod experiences a centripetal force due to its circular motion. The tension in the rod varies along its length because the segments farther from the axis of rotation must exert more force to maintain their circular path.

1. Tension as a Function of Distance

Consider a small segment of the rod at a distance r from the axis of rotation. The mass of this segment can be expressed as:

  • dm = (m/l) dr, where m is the total mass of the rod and l is its length.

The centripetal force required for this segment to maintain its circular motion is given by:

  • F_c = dm * w² * r

Substituting for dm, we have:

  • F_c = (m/l) dr * w² * r

This force is provided by the tension T(r) in the rod acting on the segment. Therefore, we can express the tension at a distance r as:

  • T(r) = ∫(m/l) * w² * r dr

Integrating from 0 to r gives:

  • T(r) = (m * w² * r²) / (2l)

2. Elongation of the Rod

To find the elongation of the rod due to the tension, we can apply Hooke's Law, which states that the elongation ΔL is proportional to the tension and the original length of the rod:

  • ΔL = (T * l) / (A * Y)

Here, A is the cross-sectional area of the rod, and Y is Young's modulus for copper. The total tension in the rod can be found by evaluating T(l), which is:

  • T(l) = (m * w² * l²) / (2l) = (m * w² * l) / 2

Substituting this into the elongation formula gives:

  • ΔL = [(m * w² * l) / 2] * l / (A * Y)

Thus, the elongation of the rod can be expressed as:

  • ΔL = (m * w² * l²) / (2 * A * Y)

Alternative Approach: Using Energy Considerations

Another way to derive the tension and elongation is through energy considerations. As the rod rotates, it possesses kinetic energy due to its motion. The work done against the tension in the rod can be related to the change in potential energy due to elongation.

Energy Approach to Tension

The kinetic energy of a small segment of the rod can be expressed as:

  • dK = (1/2) * dm * (w * r)²

Integrating this from 0 to l gives the total kinetic energy:

  • K = (1/2) * (m/l) * ∫(w² * r²) dr from 0 to l = (1/2) * (m * w² * l²) / 3

The work done by the tension in the rod as it stretches can be equated to this kinetic energy, leading to a similar expression for elongation as derived previously.

Final Thoughts

In summary, we determined the tension in the rod as a function of distance from the rotation axis and calculated the elongation using two different methods: one based on circular motion and the other using energy considerations. Both approaches yield consistent results, demonstrating the interconnectedness of physical principles in mechanics.

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