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`        A system of frictionless pulleys P1 and P2 are shown in figure. Neglecting the weights of the pulleys, the minimum pull needed at A to lift a load W will be(1) W/2(2) W/3(3) W(4) Below W/3Pls explain stepwise and in detail. `
2 years ago

Utsav Basu
70 Points
```							The min force required to pull the weight up is actually the min force required to prevent the weight from falling. Thus, to simply solve this question we can solve it backwards.  So, if we assume that the weight is not falling, a force equal to its weight must act upon it, which is W. This force is provided by the tention of the string wrapped around pulley P1, and is divided equally upon its two strands. Thus, the tension on the right strand = W/2 Now, notice that this force is actually provided by the pull at A. Thus, the min pull required to pull the weight up = W/2Option (1) is correct.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions