MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        A system contains 2 identical small bobs of mass 2kg each connected to the ends of 1m long light rod. The system is rotating about a fixed axis through centre of the rod and perpendicular to it at an angular speed of 9 rad/s. An impulsive force of average magnitude 10 N acts on one of the masses in the direction of its velocity for 0.2s. calculate new angular velocity of system
10 months ago

Answers : (1)

Sanju
106 Points
							
The impulse is provided by the force F = 10N in the direction of velocity which is perpendicular to the rod as the mass is moving in circular motion.
Therefore, the torque, T = rF = 0.5m * 10N = 5 Nm
Moment of inertia of the system abt the line passing thru its center & perpendicular to it is given by:
I = 2 * 2kg * (0.5m)= 1 kg m
We have, T = I * α
where α is the angular acceleration
Therefore, α = T / I = 5/1 = 5 rad/s2
 
So, the new angular velocity, w = w+αt   
w = w+αt = 9 + (5*0.2) = 10 rad/s
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 276 off

COUPON CODE: SELF10


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 297 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details