Sanju
Last Activity: 6 Years ago
The impulse is provided by the force F = 10N in the direction of velocity which is perpendicular to the rod as the mass is moving in circular motion.
Therefore, the torque, T = rF = 0.5m * 10N = 5 Nm
Moment of inertia of the system abt the line passing thru its center & perpendicular to it is given by:
I = 2 * 2kg * (0.5m)2 = 1 kg m2
We have, T = I * α
where α is the angular acceleration
Therefore, α = T / I = 5/1 = 5 rad/s2
So, the new angular velocity, w = w0 +αt
w = w0 +αt = 9 + (5*0.2) = 10 rad/s