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A swimmer moves through the water at a speed of 0.22 m/s. The drag force opposite this motion is 100 N. How much power is developed by the swimmer?
A swimmer moves through the water at a speed of 0.22 m/s. The drag force opposite this motion is 100 N. How much power is developed by the swimmer?

```
5 years ago

Deepak Patra
471 Points
```							We have to find out the power which is developed by the swimmer.To obtain power (P), substitute 110 N for F and 0.22 m/s for v in the equation P = Fv,P = Fv = (110 N) (0.22 m/s) = 24.2 N. m/s= (24.2 N. m/s) (1 W/1 N.m/s)= 24.2 W …… (2)Rounding off to two significant figure, the power which is developed by the swimmer will be 24 W.
```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions