a string of length 1 m is fixed at one end and a mass of 100g is attached at the other end . The string makes 2/pi rev/sec around a vertical axis through the fixd point . What is the inclination angle of the string with the vertical ?
mahima pareek , 8 Years ago
Grade 11
2 Answers
Vikas TU
Last Activity: 8 Years ago
w = 2pi*2/pi = 4 rad/s.
npw consider angle thethaa wth vertical and do comonents of Tension along horizontal and vertial and balnce them with mg and mw^2r
where from geomtery r = lsinthetha.
after balancing the eqns would be:
T = mw^2l
T = 100/1000 * 16 * 1 = 1.6 N
in vertical direcn.
Tcosthetha = mg
cosththa = 5/18
or
thetha = arccos(5/18)
Sneha Kharya
Last Activity: 7 Years ago
f = 2/piw = 2pi f = 4Tsintheta=mw^2r -(1)Tcos theta = mg &(2)Dividing equation (1) by (2)Tan theta =w^2r/gTan theta = 4*4*1/10Tan theata = 8/5
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free