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# a string of length 1 m is fixed at one end and a mass of 100g is attached at the other end . The string makes 2/pi rev/sec around a vertical axis through the fixd point . What is the inclination angle of the string with the vertical ?

Vikas TU
14149 Points
4 years ago
w = 2pi*2/pi = 4 rad/s.
npw consider angle thethaa wth vertical and do comonents of Tension along horizontal and vertial and balnce them with mg and mw^2r
where from geomtery r = lsinthetha.
after balancing the eqns would be:
T = mw^2l
T = 100/1000 * 16 * 1 = 1.6 N
in vertical direcn.
Tcosthetha = mg
cosththa = 5/18
or
thetha = arccos(5/18)
Sneha Kharya
32 Points
3 years ago
f = 2/piw = 2pi f = 4Tsintheta=mw^2r -(1)Tcos theta = mg &(2)Dividing equation (1) by (2)Tan theta =w^2r/gTan theta = 4*4*1/10Tan theata = 8/5