### Enroll For Free Now & Improve Your Performance.

×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

A string breaks on suspending a 50KG mass.One Kg mass is tied to one end of the 10m long string and revolved in a horizontal plane. find the miximum number of rotations per minute so that the string may not break. 1)67 2)57 3)47 4)97


3 years ago

## Answers : (2)

Tejus
35 Points
							we known critical mass is 500 N             mw²r= 500               w²=50   we want to have no. of rotations per minute  I.e.  no. of 2py radians per 60 sec        let no. of rotation = n    { n× 2 py/60  }²= 50 on calculating n comes to 67.52         =67 rotations approximately      I don't known whether I did wrong or right as I did it in my first attempt  only the last line was tricky rest easy one    thank you

3 years ago
Arun
24741 Points
							Length r= 10 mMass m= 1 kgCentripetal force F = 50 kg wt = 50* 9.8 NLet n be the maximum number of revolutions made persecond without breaking string.Then F = m*r*w2 = m r (2$\pi$ n)250 * 9.8 = 1*10 (44/7 *  n)2490 = 395.10 n2n = 1.11 revolution per secondHence revolution per minute = 1.11* 60 = 66.66 = 67

3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details