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a stone thrown down with speed u takes a time t1 to reach the ground while another stone thrown upwards from the same point woth the same speed takes time t2 the maximim height the second stone reaches from the ground is
a stone thrown down with speed u takes a time t1 to reach the ground while another stone thrown upwards from the same point woth the same speed takes time t2 the maximim height the second stone reaches from the ground is

```
3 years ago

Shailendra Kumar Sharma
188 Points
```							 lets say the stones were thrown from a height H Now, the case of t1 the stone was thrown downward. H=ut1+(1/2)gt12---------------(a) for second case -H =ut2+(1/2)gt22 …............(b)Maximum height with respect to the level H can be calculated by v2=u2-2as => s= u2/2g so with respect to ground the maximum height will be H+u2/2g But H is not given So we have to find that out which can be found by subtraction a and b equations2H= {ut1+(1/2)gt12} – {ut2+(1/2)gt22} =u(t1-t2)-(1/2)g(t12-t22) H= {u(t1-t2)-(1/2)g(t12-t22)}/2so the maxium height with respect to groun is ={u(t1-t2)-(1/2)g(t12-t22)}/2+u2/2g
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions