A stone is thrown vertically upwards with an initial velocity u from the top of a tower,reaches the ground with a velocity of 3u.The height of the tower is???
harshal pawar , 7 Years ago
Grade 11
3 Answers
IHate Ppts
Last Activity: 7 Years ago
When it reaches maximum height and falls down till the point of projection, the velocity at that instant and projection will be same. Using that logic, we will solve it.
Firstly, we use V=U+AT to find time.
3u=u+10t, t=u/5
Substitute this time in displacement formula.
S=u(u/5)+1/2 * 10(u/5)2
s = 10u2/25
harshal pawar
Last Activity: 7 Years ago
It is solved by the equation v2=u2+2as
And the answer 4u^2/g..
Cheers.
Dt
Last Activity: 6 Years ago
H be height v =velocity g= gravitational force or acceleration
H=v2-u2/2g
H=9u2-u2/2g
H=8u2/2g
H=4u2/g is the height of the tower
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