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A stone is thrown horizontally with the velocity of 15 m/s. Determine the tangential and normal accelerations of the stone in one second after it begins to move
In x direcn.,Vx = 15cos(thetha)In y direcn.,Vy = 15sin(thetha) – g*1 acclern. in x dircn. = > (Vx – 15costhetha)/1 = 0accln. in y dircn. = > Vy – 15sinthetha)/1 = > -gHence net acclen.is in downward direcn that is => g m/s^2
At=2g/√13 an=3g/√13 ßhhsejuxjshuxxeiis Ed uecudjd it up on my way back to you as well as well and that the message and all of fruit
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