A stone is thrown horizontally with the velocity of 15 m/s. Determine the tangential and normal accelerations of the stone in one second after it begins to move
Sourav Paul , 8 Years ago
Grade 11
2 Answers
Vikas TU
Last Activity: 8 Years ago
In x direcn.,
Vx = 15cos(thetha)
In y direcn.,
Vy = 15sin(thetha) – g*1
acclern. in x dircn. = > (Vx – 15costhetha)/1 = 0
accln. in y dircn. = > Vy – 15sinthetha)/1 = > -g
Hence net acclen.is in downward direcn that is => g m/s^2
Sonia
Last Activity: 7 Years ago
At=2g/√13 an=3g/√13 ßhhsejuxjshuxxeiis Ed uecudjd it up on my way back to you as well as well and that the message and all of fruit
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