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`        A stone is released from the top of the tower. It covers 24.5m distance in the last second of its journey. What is the height of the tower `
one year ago

Khimraj
3008 Points
```							Height of the tower = HTotal time taken to reach the ground = TH = 0.5gT^2 ——(1)H - 24.5 = 0.5g * (T - 1)^20.5gT^2 - 24.5 = 0.5g * (T^2 + 1 - 2T)0.5gT^2 - 24.5 = 0.5gT^2 + 0.5g - gTgT - 24.5 = 0.5g10T - 24.5 = 510T = 29.5T = 2.95 sSubstitute T = 2.95 s in equation (1)H = 0.5gT^2= 0.5 * 10 * (2.95)^2= 43.5 mHeight of the tower is 43.5 m
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions