A stone is projected with a velocity 20√2 m/s at an angle of 45° to t

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Sonai Grade: 12th pass


                        A stone is projected with a velocity 20√2 m/s at an angle of 45° to the horizontal .The average velocity of stone during the motion from starting point to its maximum height is

2 years ago

Answers : (3)

Khimraj

3007 Points

							average velocity = (total displacement)/(time taken)
max height = u²cos²45/2*g = 20 m
Half range = u²sin2*45/2*g = 40 m
time taken = 2usin45/g = 4 sec
total displacement = 
so average velovity = /4 =  m/s
Hope it clears. If you like answer then please approve it.

2 years ago

naman

30 Points

							 average velocity = (total displacement)/(time taken)
max height = u²cos²45/2*g = 20 m
Half range = u²sin2*45/2*g = 40 m
Time half the time of flight that is 2 seconds
Average velocity equals to total displacement upon total time therefore average velocity equals to 10√5

2 years ago

SANJAY MODI

13 Points

							Initial velocity:
Final velocity:
Therefore average velocity:
 
as the motion is uniformly accelerated:
Putting values:
 m/s
In magnotude average velocity:
  m/s