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A stone is projected with a velocity 20√2 m/s at an angle of 45° to the horizontal .The average velocity of stone during the motion from starting point to its maximum height is A stone is projected with a velocity 20√2 m/s at an angle of 45° to the horizontal .The average velocity of stone during the motion from starting point to its maximum height is
average velocity = (total displacement)/(time taken)max height = u2cos245/2*g = 20 mHalf range = u2sin2*45/2*g = 40 mtime taken = 2usin45/g = 4 sectotal displacement = so average velovity = /4 = m/sHope it clears. If you like answer then please approve it.
average velocity = (total displacement)/(time taken)max height = u2cos245/2*g = 20 mHalf range = u2sin2*45/2*g = 40 mTime half the time of flight that is 2 secondsAverage velocity equals to total displacement upon total time therefore average velocity equals to 10√5
Initial velocity:Final velocity:Therefore average velocity: as the motion is uniformly accelerated:Putting values: m/sIn magnotude average velocity: m/s
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