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A stone is projected horizontally with speed V from a height h above ground a horizontal wind is blowing in a direction opposite to velocity of projection and gives a stoner constant horizontal acceleration f (in the direction opposite to initial velocity). As a result the stone falls on ground at a point vertically below the point of projection then the value of h in term of f,g,v is (g is acceleration due to gravity)

Apurv patel , 7 Years ago
Grade 11
anser 1 Answers
Eshan
Dear student,

During the time of flight the particle must have zero horizontal displacement.

Time of flight=t_f=\sqrt{\dfrac{2h}{g}}

Hence since the horizontal displacement is zero,

0=ut_f-\dfrac{1}{2}ft_f^2
\implies \dfrac{2u}{f}=t_f=\sqrt{\dfrac{2h}{g}}
\implies \dfrac{4u^2}{f^2}=\dfrac{2h}{g}
\implies h=\dfrac{2u^2g}{f^2}
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