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Grade: 12th pass

A stone is projected from level ground such that it's horizontal and vertical component of initial velocity are 10 and 20m/s .Then the angle between velocity vector of stone one second before and after it attain maximum height is ??
A stone is projected from level ground such that it's horizontal and vertical component of initial velocity are 10 and 20m/s .Then the angle between velocity vector of stone one second before and after it attain maximum height is ??


2 years ago

## Answers : (1)

Khimraj
3007 Points
							speed of stone at time tv = 10 $\hat{i}$  + (20 – gt)$\hat{j}$tme taken by stone to attain max height = 20/g = 2 secso velocity at t= 1 secv1 = 10$\hat{i}$ + 10$\hat{j}$and velocity at t = 3 secv2 = 10$\hat{i}$ – 10$\hat{j}$as v1.v2 = 0so angle between v1 and v2 is 90oHope it clears.

2 years ago
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