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A stone is projected from level ground such that it's horizontal and vertical component of initial velocity are 10 and 20m/s .Then the angle between velocity vector of stone one second before and after it attain maximum height is ??

A stone is projected from level ground such that it's horizontal and vertical component of initial velocity are 10 and 20m/s .Then the angle between velocity vector of stone one second before and after it attain maximum height is ??

Grade:12th pass

1 Answers

Khimraj
3007 Points
5 years ago
speed of stone at time t
v = 10 \hat{i}  + (20 – gt)\hat{j}
tme taken by stone to attain max height = 20/g = 2 sec
so velocity at t= 1 sec
v1 = 10\hat{i} + 10\hat{j}
and velocity at t = 3 sec
v2 = 10\hat{i} – 10\hat{j}
as v1.v2 = 0
so angle between v1 and v2 is 90o
Hope it clears.

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