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A stone is projected at anangle of 60 deegree from the ground level strikes at an angle 30 deegree on the roof of a building of height ‘h’.then the speed of projection of the stone is: (A)2gh 0.5 (B)6gh 0.5 (C)3gh 0.5 (D)gh 0.5 pls give ans with solution....
A stone is projected at anangle of 60 deegree from the ground level strikes at an angle 30 deegree on the roof of a building of height ‘h’.then the speed of projection of the stone is:(A)2gh0.5  (B)6gh0.5   (C)3gh0.5 (D)gh0.5 pls give ans with solution....

```
4 years ago

Vikas TU
14149 Points
```							Components in x and y direction of initial velocity with 60 degree are:ucos60 and usin60 respectively.At h height distance,tan30 = Vy/ucos60Vy = u/2root3Further Distance in y – direction :Vy^2 – (usin60)^2 = 2as(u/2root3)^2 – (uroot3/2)^2  = -2gsOn solving we get,u = root(3gh)that is (C) option.
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions