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Grade 11Mechanics

a stone is dropped from the roof of building takes 5 sec to reach the ground.The sound of striking is heard after 5.4 sec after the stone is dropped.The velocity of sound is?

Gauri Padole

8 Years agoGrade 11

4 Answers

Aniket Tiwari

8 Years ago

v= ut + at sq

v= 1/2* 9.8*5*5

s= v sq/2g

i think also that the question is is also incomplite u should check the question again because u didnt had mention the hight of the roof from ground than also i had answer some parts from it sq means square of the given value

swarup kumar majee

8 Years ago

u=0,t=5sec,a=9.8m/s²

so ,hieght of the building is h=1/2at²

h=122.5m

sound is heard after 0.4sec after the sound is produced

so velocity of sound is=122.5/0.4=306.25 m/s

Jefina Mathew

8 Years ago

Here u=0,t=5s,a=10m/s^2S=1/2gt^2S=125mSound is heard after 0.4sVelocity of sound = distance travelled/timeVelocity=125/0.4=312.5

Nasrin

8 Years ago

We know s=ut+1/2at^2.putting u=0,a=10 and t=5 we get s=125m.so the building is 125m high.Sound is heard after 5.4-5=0.4 s.Again we know, velocity *time=distanceSo, v*0.4=125,v=125/0.4=312.5

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