×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
a stone is dropped from a top of building covers 36% of total distance in its last second of its motion. the height of building is ?
a stone is dropped from a top of building covers 36% of total distance in its last second of its motion. the height of building is ?

```
3 years ago

Arun
25768 Points
```							We can write 36/100 = 9/25 alsoLet ‘n’ be the time of fall.Using, S = ut + ½ at2=> h = 0 + ½ gn2=> n = [(2h)/g]1/2Distance travelled in the nth second is,Sn = u + (a/2)(2n – 1)=> 9h/25 = 0 + (9.8/2)[2{(2h)/g}1/2 – 1]=> 9h/25 = 4.9[2{2h/9.8}1/2 – 1]Solving for h we get,h = 122.5 m
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions