Grade 11Mechanics

a stone is dropped from a height of 45m. what will be the distance traveeled by it during the last one second of its motion??

kartikeya sahani

8 Years agoGrade 11

2 Answers

Hiba Musthafa

Approved Tutor Answer8 Years ago

total time taken=(2h/g)1/2 = (2*45/10) ½ = (9) ½ = 3

distance travelled in last sec = S= u + a/2 (2n-1)

S= 0 + 10/2 (2*3 – 1)

= 25 m

Rawnak

7 Years ago

Time taken = s=ut + 1\2at×t

45 = 1/2×10t×t = ✓9=3

S= u+a

( n-1/2)

0+10 ( 3 -1/2)

25m

Use formula of nth sec

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a stone is dropped from a height of 45m. what will be the distance traveeled by it during the last one second of its motion??

kartikeya sahani

2 Answers

Hiba Musthafa

Rawnak

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