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a stone is dropped from a height of 45m. what will be the distance traveeled by it during the last one second of its motion??
a stone is dropped from a height of 45m. what will be the distance traveeled by it during the last one second of its motion??

```
3 years ago

Hiba Musthafa
20 Points
```							total time taken=(2h/g)1/2 = (2*45/10) ½  = (9) ½ = 3distance travelled in last sec = S= u + a/2 (2n-1)S= 0 + 10/2 (2*3 – 1)= 25 m
```
3 years ago
Rawnak
15 Points
```							Time taken = s=ut + 1\2at×t  45 = 1/2×10t×t = ✓9=3 S= u+a( n-1/2)0+10 ( 3 -1/2) 25mUse formula of nth sec
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions