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A stone falls from rest. The distance covered by the stone in the last second of its motion is equal to the distance covered by it during the first three seconds. How long does the stone take to reach the ground?
First take out distance covered by first 3 sec using the formula S=ut+1/2at^2 it is equal to 45mLet the total time taken be tTake out distance covered in t sec and in (t-1)sec subtract both the distance which is equal 45Solve equation to get t.Answer is 5sec
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