×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
A stone falls from rest. The distance covered by the stone in the last second of its motion is equal to the distance covered by it during the first three seconds. How long does the stone take to reach the ground?
A stone falls from rest. The distance covered by the stone in the last second of its motion is equal to the distance covered by it during the first three seconds. How long does the stone take to reach the ground?

```
4 years ago

Garima
19 Points
```							First take out distance covered by first 3 sec using the formula S=ut+1/2at^2 it is equal to 45mLet the total time taken be tTake out distance covered in t sec and in (t-1)sec subtract both the distance which is equal 45Solve equation to get t.Answer is 5sec
```
4 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions