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`        A stone falls from a balloon , ascending with a velocity of 10m/s and reaches the ground in 17 seconds, how high was the balloon when the stone was dropped?`
one year ago

Arun
22987 Points
```
When it is released, the stone will rise 5m before stopping. 0=100–2aD. D=5m. Gravitational acceleration, a, is 10m/s^2
This will take 1 second.
16 seconds later the stone will hit the ground. The stone will fall 1280 m in 10 seconds (D=1/2 aT^2)
So the release point was 5 meters below 1280 meters, or 1275 meter
Regards

```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions