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Grade: 12th pass
        A stone and mass m is thrown from earth`s surface at an angle theta to the horizontal with an initial velocity u. Find out the average force just t second after the beginning of motion
3 years ago

Answers : (1)

Vikas TU
9484 Points
							
After t seconds, final velocites in x and y direcns respectively are:
Vx = ucostheta
Vy = usintheta – gt
Net velocity = root((ucosthetha)^2 + (usintheta – gt)^2)
dV/dt = (usintheta – gt)*(-g)/((ucosthetha)^2 + (usintheta – gt)^2)
 
Force = m*a = > m*dV/dt = > m*(usintheta – gt)*(-g)/((ucosthetha)^2 + (usintheta – gt)^2) Netwon.
3 years ago
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