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A "stiff" spring has a force law given by F = – kx 3 . The work required to stretch the spring from the relaxed state x = 0 to the stretched length x = l is W0. In terms of W 0 , how much work is required to extend the spring from the stretched length 1 to the length 2l?
A "stiff" spring has a force law given by F = – kx3. The work required to stretch the spring from the relaxed state x = 0 to the stretched length x = l is W0. In terms of W0, how much work is required to extend the spring from the stretched length 1 to the length 2l?

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5 years ago

Navjyot Kalra
654 Points
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5 years ago
Hasan Naqvi
97 Points
```							F = – kx3W = ∫F.dxW= – ∫kx3.dx= – kx4/4Wo = -kl4/4W in stretching from 0 to 2l= -16kl4/4 = 16 WoWork in stretching from l to 2l = 15Wo
```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions