a stiff horizontal spring of weight W and force constant k is suspended in a horizontal position by two light strings attached to its two ends. Each strings makes an angle theta with the vertical. The extension of the spring is:
Arulyan Asokan , 8 Years ago
Grade 11
2 Answers
Anirudh Raghavan S
Last Activity: 8 Years ago
The tensions are equal, so the sum of their horizontal components is equal to the tension in the spring, so
2 T sin(theta) = kx.
Also, the sum of the vertical components of the tension equals the weight, or
2Tcos(theta)=W
Solve for T in the latter and plug into the former, solve for x and you get:
x = (2W tan (theta))/k
Thriller
Last Activity: 5 Years ago
Horizontal components of tensions are equal in magnitude but they are different directions, so
Tsin(theta)-Tsin(theta)=kx
=> x=0
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