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Grade 11Mechanics

A steel wire and a copper wire of equal length and equal cross sectional area are joined end to end. fnd stress developed between two wires and strain developed.

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8 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

When we connect a steel wire and a copper wire end to end, we create a system where both materials will experience stress and strain under an applied load. To understand how stress and strain are distributed in this setup, we need to consider the properties of both materials, particularly their Young's moduli, which measure their stiffness.

Understanding Stress and Strain

Stress is defined as the force applied per unit area, while strain is the deformation experienced by a material in response to that stress. The relationship between stress and strain is governed by Hooke's Law, which states that stress is proportional to strain within the elastic limit of the material.

Material Properties

For our analysis, we need to know the Young's modulus (E) for both steel and copper:

  • Steel: Approximately 200 GPa (gigapascals)
  • Copper: Approximately 110 GPa

Calculating Stress in Each Wire

When a tensile load (force) is applied to the combined wire system, both wires will experience the same force (F) because they are in series. The stress (σ) in each wire can be calculated using the formula:

σ = F / A

Where A is the cross-sectional area of the wire. Since both wires have equal cross-sectional areas, they will experience the same stress:

σ_steel = σ_copper = F / A

Determining Strain in Each Wire

Next, we need to find the strain (ε) in each wire. Strain is given by:

ε = σ / E

Substituting the stress into this equation for both materials, we have:

ε_steel = (F / A) / E_steel

ε_copper = (F / A) / E_copper

Relationship Between Strain and Length

Since the wires are connected end to end, the total elongation (ΔL) of the system is the sum of the elongations of each wire:

ΔL = ΔL_steel + ΔL_copper

Where:

  • ΔL_steel = ε_steel * L_steel
  • ΔL_copper = ε_copper * L_copper

Given that both wires are of equal length (L), we can express the total elongation in terms of the applied force and the material properties.

Final Thoughts

In summary, both wires will experience the same stress due to their series connection, but the strain will differ because of their different Young's moduli. The steel wire, being stiffer, will have a lower strain compared to the copper wire. This difference in strain is crucial in applications where materials are combined, as it can lead to uneven elongation and potential failure if not properly accounted for.