A steel rod of cross-sectional area 4 cm2 and length 2 m shrinks by 0.1 cm as the temperature decreases in night . If the rod is clamped at both ends during the day hours, find the tension developed in it during night hours. Young modulus of steel = 1.9 × 1011 N m-2.

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Jitender Pal · Answer

Sol. Y = F/A L/∆L ⇒ F = YA ∆L/L

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A steel rod of cross-sectional area 4 cm2 and length 2 m shrinks by 0.1 cm as the temperature decreases in night . If the rod is clamped at both ends during the day hours, find the tension developed in it during night hours. Young modulus of steel = 1.9 × 1011 N m-2.

A steel rod of cross-sectional area 4 cm2 and length 2 m shrinks by 0.1 cm as the temperature decreases in night . If the rod is clamped at both ends during the day hours, find the tension developed in it during night hours. Young modulus of steel = 1.9 × 1011 N m-2.

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A steel rod of cross-sectional area 4 cm2 and length 2 m shrinks by 0.1 cm as the temperature decreases in night . If the rod is clamped at both ends during the day hours, find the tension developed in it during night hours. Young modulus of steel = 1.9 × 1011 N m-2.

A steel rod of cross-sectional area 4 cm2 and length 2 m shrinks by 0.1 cm as the temperature decreases in night . If the rod is clamped at both ends during the day hours, find the tension developed in it during night hours. Young modulus of steel = 1.9 × 1011 N m-2.

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