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a stair case contains 3 steps each of10 cm high and 20 cm wide .whatshould be minimum horizontal velocity of a ball rolling off the uppermost plane so as to hit directlythe lowest plane

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8 months ago

```							hit directly the lowest plane the ball has to cross the point B.From A to B, the  ball has to travel to horizontal distance equal 40cm =40mand vertical distance of 20cm=0.2m. Let the time taken to reach point be t.u=0 m/sh=0.2mfrom the equation, h=ut+1/2gt² we get0.2=0+1/2 x9.8 t²t²=0.4/9.8t²=0.04t=0.2Let v be the horizontal velocity of ball than the horizontal distance travelled by the ball=0.2vin order to clear the point B it must be equal to 0.40.2v=0.4v=2m/s∴So minimum velocity required to to hit the lowest floor  is 2 m/s.
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8 months ago
```							Dear student in a friction-less rolling of the ball, the number, height and width of the steps have no effect on the horizontal velocity.Falling off the edge of a higher step to a lower one, the ball gains some vertical velocity due to gravitational acceleration, but the vertical momentum gained is absorbed on impact with the lower step. So the ball maintains its original initial horizontal velocity.If rolling friction is present, one should expect some decrease from the initial velocity.Hope this helps Good Luck
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8 months ago
```							Dear Student, Let the time taken to reach point be t.u=0 m/sh=0.2mfrom the equation, h=ut+1/2gt²we get0.2=0+1/2 x9.8 t²t²=0.4/9.8t²=0.04t=0.2Let v be the horizontal velocity of ball than the horizontal distance travelled by the ball=0.2vin order to clear the point B it must be equal to 0.40.2v=0.4v=2m/s∴So minimum velocity required to to hit the lowest floor  is 2 m/s.   Regards
```
6 months ago
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