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A square plate is thrown horizontally on a rough horizontal surface .Find minimum value of coefficient of friction so that the plate topples
For toppling about the extreme bottom right corner of the sqaure plate thee torque of force should be greater than mg then only the plate can topple.Let us take the side as "a" unit.So tau(F)>tau(mg) F.a>mg.aF>mg ........ (1)To avoid sliding Fmg (from (1))u>1So the answer is 1.
For the block to topple frictional torque should be greater than the normal torque acting on the extreme rightN x a/2 N x a/2 1 so minimum coefficient of friction is 1.thank you
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