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A spring of spring constant 5 × 10 3 N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm is a) 12.50 N-m b) 18.75 N-m c) 25.00 N-m d) 6.25 N-m

A spring of spring constant 5 × 103 N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm is
a) 12.50 N-m
b) 18.75 N-m
c) 25.00 N-m
d) 6.25 N-m

Grade:12th pass

4 Answers

Vasantha Kumari
askIITians Faculty 38 Points
7 years ago

181-1425_Workdone_solution.jpg
Vaishnavi
13 Points
3 years ago
Here, W=1/2k(x22-x12)
               = 1/2×5×103((10/100)2-(5/100)2)
               =1/2×5×103/104(100-25)
               =18.75J
Hence the work required to stretch the spring further by another 5cm is 18.75 N-m
Thanks and regards
             
Sohail
15 Points
2 years ago
Work done by spring=1/2k(x22-x12)
K=5×103N/m
X2=10×10-2m
X1=5+10-2m
W=1/2×5×103(100-25)10-4
W=18.75N-m
 
Kushagra Madhukar
askIITians Faculty 629 Points
one year ago
Dear student,
Please find the attached solution to your problem.
 
W = 0.5k(x22 – x12)
               = 0.5 × 5 × 103((10/100)2 - (5/100)2)
               = 0.5 × 5 × 103/104 (100-25)
               =18.75 J
Hence the work required to stretch the spring further by another 5cm is b) 18.75 N-m
 
Hope it helps.
Thanks and regards,
Kushagra

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