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Grade: 12th pass
        
A spring of spring constant 5 × 103 N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm is
a) 12.50 N-m
b) 18.75 N-m
c) 25.00 N-m
d) 6.25 N-m
4 years ago

Answers : (2)

Vasantha Kumari
askIITians Faculty
38 Points
							
181-1425_Workdone_solution.jpg
4 years ago
Vaishnavi
13 Points
							
Here, W=1/2k(x22-x12)
               = 1/2×5×103((10/100)2-(5/100)2)
               =1/2×5×103/104(100-25)
               =18.75J
Hence the work required to stretch the spring further by another 5cm is 18.75 N-m
Thanks and regards
             
one month ago
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