A spring of spring constant 5 × 10 3 N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm is a) 12.50 N-m b) 18.75 N-m c) 25.00 N-m d) 6.25 N-m

Question

Vasantha Kumari · Answer

Vaishnavi · Answer

Here, W=1/2k(x 2 2 -x 1 2 ) = 1/2×5×10 3 ((10/100) 2 -(5/100) 2 ) =1/2×5×10 3 /10 4 (100-25) =18.75J Hence the work required to stretch the spring further by another 5cm is 18.75 N-m Thanks and regards

Sohail · Answer

Work done by spring=1/2k(x 2 2 -x 1 2 ) K=5×10 3 N/m X 2 =10×10 -2 m X 1 =5+10 -2 m W=1/2×5×10 3 (100-25)10 -4 W=18.75N-m

Kushagra Madhukar · Answer

Dear student, Please find the attached solution to your problem. W = 0.5k(x 2 2 – x 1 2 ) = 0.5 × 5 × 10 3 ((10/100) 2 - (5/100) 2 ) = 0.5 × 5 × 10 3 /10 4 (100-25) =18.75 J Hence the work required to stretch the spring further by another 5cm is b) 18.75 N-m Hope it helps. Thanks and regards, Kushagra

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A spring of spring constant 5 × 10 3 N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm is a) 12.50 N-m b) 18.75 N-m c) 25.00 N-m d) 6.25 N-m

A spring of spring constant 5 × 10³ N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm is
a) 12.50 N-m
b) 18.75 N-m
c) 25.00 N-m
d) 6.25 N-m

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A spring of spring constant 5 × 10 3 N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm is a) 12.50 N-m b) 18.75 N-m c) 25.00 N-m d) 6.25 N-m

A spring of spring constant 5 × 103 N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm isa) 12.50 N-mb) 18.75 N-mc) 25.00 N-md) 6.25 N-m

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A spring of spring constant 5 × 10³ N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another 5 cm is
a) 12.50 N-m
b) 18.75 N-m
c) 25.00 N-m
d) 6.25 N-m