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Grade 12th passMechanics

A spherical ball of ice has radius R0 and it's rotating with angular speed w(omega) about an axis passing through it's centre. At time t=0, it starts acquiring mass because the moisture(at rest) around it starts to freeze on it uniformly. As a result it's radius increases as R(t) = R0 + kt, where k is a constant. Find out the relation between the angular speed and time.

Profile image of Somoshree Chatterjee
10 Years agoGrade 12th pass
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ApprovedApproved Tutor Answer1 Year ago

To find the relationship between the angular speed and time as the spherical ball of ice acquires mass, we can apply the principles of conservation of angular momentum. When the ice ball starts to grow in size, its moment of inertia changes, which in turn affects its angular speed. Let's break this down step by step.

Understanding Angular Momentum

Angular momentum (L) is defined as the product of the moment of inertia (I) and the angular velocity (ω):

L = I * ω

For a solid sphere, the moment of inertia is given by:

I = (2/5) * m * R²

where m is the mass of the sphere and R is its radius. As the sphere gains mass, both m and R will change over time.

Mass and Radius Over Time

Initially, at time t = 0, the radius of the sphere is R0. As time progresses, the radius increases according to the equation:

R(t) = R0 + kt

Assuming the density of the ice remains constant, the mass of the sphere can be expressed as:

m(t) = ρ * V(t)

where ρ is the density and V(t) is the volume of the sphere:

V(t) = (4/3) * π * R(t)³

Substituting R(t) into the volume equation gives:

V(t) = (4/3) * π * (R0 + kt)³

Calculating Moment of Inertia

Now, substituting V(t) into the mass equation:

m(t) = ρ * (4/3) * π * (R0 + kt)³

Thus, the moment of inertia becomes:

I(t) = (2/5) * m(t) * R(t)²

Substituting m(t) and R(t) into this equation yields:

I(t) = (2/5) * ρ * (4/3) * π * (R0 + kt)³ * (R0 + kt)²

Applying Conservation of Angular Momentum

Since no external torques are acting on the system, angular momentum is conserved:

L(0) = L(t)

At t = 0, the angular momentum is:

L(0) = I(0) * ω(0)

At time t, we have:

L(t) = I(t) * ω(t)

Setting these equal gives us:

I(0) * ω(0) = I(t) * ω(t)

Finding the Relationship

From this equation, we can solve for ω(t):

ω(t) = (I(0) * ω(0)) / I(t)

As we substitute I(0) and I(t) into this equation, we can express ω(t) in terms of time:

Since I(0) is constant and I(t) increases as the radius increases, we can see that ω(t) will decrease over time as the sphere gains mass and increases in size.

Final Expression

To summarize, the relationship between angular speed and time can be expressed as:

ω(t) = (I(0) * ω(0)) / [(2/5) * ρ * (4/3) * π * (R0 + kt)³ * (R0 + kt)²]

This shows that as time progresses, the angular speed ω(t) decreases due to the increasing moment of inertia as the radius of the sphere grows. The exact form of this relationship can be further simplified depending on the values of R0, k, and ρ.