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        a sphere of mass two kg is resting inside a cube.The cube is moving  with velocity of 5t along x axis+2talong y axis in m/s.here t is in seconds.all surface are smooth.the sphere is at rest with respect to the cube.hat is totalforce exerted by the sphere on the cube
one year ago

Arun
23357 Points
							Dear student

a(x) = dv(x)/dt = 5
a(y) = d v(y)/dt = 2
Now
Fx = m* a(x) = 2* 5 = 10
Fy = m* [a(y)+g] = 2*(2+10) = 24
F = $\sqrt$(F²x + F²y)
F = $\sqrt$100+576 = $\sqrt$676
F = 26 N

Regards

one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions