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Grade: 11
        
a solid sphere of mass m is situated on a horizontal surface and a tangential force act at the top of the sphere. if the sphere rolls without slipping then the accelaration of the centre of sphere would be – . pls give the answer and explain it in steps .
3 years ago

Answers : (3)

Vikas TU
11137 Points
							
Torque from the centre of Rotation we get,
T = I*a
a is angular accln.
F*R = ((2/5)MR^2 + MR^2)a
we get a = 5F/7MR rad/sec.
Now accln. = a/R
Hence Acom = 5F/7M
where F is the tangential constant Force And M is th mass of the sphere.
3 years ago
Karan Gupta
51 Points
							
FR – fR = (2/5)MR^2*a/R
F – f = (2/5)Ma....................(1)
F + f = Ma...........................(2)
 
Adding, 2F = (7/5)Ma
a = 10F/7m ….......................Answer
one year ago
Suraj
11 Points
							
Torque from the centre of Rotation we get,
T = I*a
a is angular accln.
F*R = ((2/5)MR^2 + MR^2)a
we get a = 5F/7MR rad/sec.
Now accln. = a/R
Hence Acom = 5F/7M
where F is the tangential constant Force And M is th mass of the sphere.    Ok
one year ago
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