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`        a small steel ball falls through a syrup at constant speed of 10 m/s. if steel ball is pulled upwards with a force equal to twice its effective weight, how fast will it move upwards`
3 years ago

Vikas TU
10558 Points
```							From work energy theorem,mgh = 0.5mv^2v = root(2gh)orh = 100/2g => 5 meter.Force with it has been pulled upwards = 2mg = ma => a = 2g m/s^20^2 = u^2 – 2*2g*5u^2 = 200u = 10root(2) m/s
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions