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Grade: 11

                        

A small mass slides down an inclined plane of inclination ‘s’ with horizontal.The coefficient of friction ‘D’ =D 0 x where x is the distance through which the mass slides down and D 0 is a positive constant.find the distance covered by the mass before it comes to rest.

4 years ago

Answers : (1)

Vikas TU
12279 Points
							
Net Force = mgsin(s) – Dmgcos(s)
Net acceleration = gsin(s) – D0xgcos(s)
a = vdv/dx =  gsin(s) – D0xgcos(s)
      vdv =  gsin(s)dx – D0xgcos(s)dx
Integerating botth sides and with limit of v 0to 0.
v^2/2 = xgsin(s) – D0x^2gcos(s)/2
 xgsin(s) – D0x^2gcos(s)/2 = 0
Hence, x = (2/Do)(sins/cos(s)) =  > (2tan(s))/Do m.
4 years ago
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