Adarsh
Last Activity: 8 Years ago
Here, frictional force = μmg
μ – coeffiecient of friction between the blocks wher
m – mass of the small block
g – acceleration due to gravity
∴, F=0.5×20×10=100
Now, as the applied force is less than the frictional force there is no relative displacement between the two blocks.
So there is no work done by the frictional force.
Hence work done by the frictional force in 2 sec = 0.
Hope you understand my solution.