Flag Mechanics> A small block of mass 20 kg rests on a bi...
question mark

A small block of mass 20 kg rests on a bigger block of mass 30kg , which lies on smooth horizontal plane. Initially the whole system is at rest. The coefficient of friction between the blocks is 0.5 . A horizontal force F=50N is applied on the lower block. Find the work done by frictional force on upper block in t=2sec

Sudhanshu Swarnim , 8 Years ago
Grade 11
anser 1 Answers
Adarsh

Last Activity: 8 Years ago

Here, frictional force = μmg 
 μ – coeffiecient of friction between the blocks wher
m – mass of the small block
g – acceleration due to gravity
 ∴, F=0.5×20×10=100
Now, as the applied force is less than the frictional force there is no relative displacement between the two blocks.
So there is no work done by the frictional force.
Hence work done by the frictional force in 2 sec = 0.
 
Hope you understand my solution.

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...