×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# A small ball starts moving from A over a fixed track as shown in the figure. Surface AB has friction. From A to B the ball rolls without slipping. Surface BC is frictionless. K A , K B and K C are kinetic energies of the ball at A, B and C, respectively. Then [figure] a) h A >h C ; K B > K C b) h A >h C ; K C > K A c) h A = h C ; K B = K C d) h A C ; K B > K C

6 years ago

Arun Kumar
IIT Delhi
256 Points
Hi

$\\E_A=mgh_A+K_A \\E_B=K_B \\E_C=mgh_C+K_C \\since the energy is conserved \\E_A=E_C=E_C \\=>K_B>K_A \\=>K_B>K_C \\solving first and last we get \\h_A-h_C=\frac{K_C-K_A}{Mg}$

so A,B,D

Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty

6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions