A slef-propelled vehicle of mass m , whose engine dilivers a constant power P has an accerlation a=(P/mv) .(assume that there is no friction) In order to increase its velocity from V 1 to V 2 , the distance it has to travel is will be

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Arun · Answer

Dear student P=FV P=mav P=mv . dv/ds . v P/m.ds =v^2.dv Integrate both sides under limits V from v1 to v2 ds from 0 to S We get (v^3/3)v1tov2=P/m.s 1/3(v2^3-v1^3)=P/m.S M/3P(v2^3-v1^3)=S Regards Arun

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A slef-propelled vehicle of mass m , whose engine dilivers a constant power P has an accerlation a=(P/mv) .(assume that there is no friction) In order to increase its velocity from V 1 to V 2 , the distance it has to travel is will be

A slef-propelled vehicle of mass m , whose engine dilivers a constant power P has an accerlation a=(P/mv) .(assume that there is no friction) In order to increase its velocity from V₁ to V₂, the distance it has to travel is will be

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A slef-propelled vehicle of mass m , whose engine dilivers a constant power P has an accerlation a=(P/mv) .(assume that there is no friction) In order to increase its velocity from V 1 to V 2 , the distance it has to travel is will be

A slef-propelled vehicle of mass m , whose engine dilivers a constant power P has an accerlation a=(P/mv) .(assume that there is no friction) In order to increase its velocity from V1 to V2, the distance it has to travel is will be

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A slef-propelled vehicle of mass m , whose engine dilivers a constant power P has an accerlation a=(P/mv) .(assume that there is no friction) In order to increase its velocity from V₁ to V₂, the distance it has to travel is will be